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"content": "# 1+2+3+4+...+100 = **5,050**\n\n## Solution Method:\n\nThis is the sum of the first 100 natural numbers. We can use the formula:\n\n**Sum = n(n+1)/2**\n\nWhere n = 100\n\n**Calculation:**\n- Sum = 100 × 101 / 2\n- Sum = 10,100 / 2\n- Sum = **5,050**\n\n### The Story Behind It:\nThis formula is famously attributed to Carl Friedrich Gauss, who supposedly discovered it as a young student when asked to sum the numbers 1 to 100. He realized you could pair numbers from opposite ends: (1+100), (2+99), (3+98), etc., each pair summing to 101, with 50 such pairs, giving 50 × 101 = 5,050.",
"reasoning_content": "This is a classic mathematical problem asking for the sum of integers from 1 to 100.\n\nThere's a famous formula for this: the sum of the first n natural numbers is n(n+1)/2\n\nFor n = 100:\nSum = 100 × 101 / 2\nSum = 10,100 / 2\nSum = 5,050\n\nSo 1+2+3+4+...+100 = 5,050",
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